Problem


Logic

분석

  • 문제 유형 (알고리즘…)
  • 제약 조건 (인풋 크기, 예외 값, 시공간 복잡도…)

설계

  1. 알고리즘 선택
  2. 자료구조 선택
  3. 수도 코드 작성
  4. 정합판단
  • 1 ~ 3과정으로 도출된 로직이 문제를 해결하는가
    • 그렇다 구현
    • 잘 모르겠다 구현
    • 아니다 1번부터 다시 점검

구현

  • 로직 검증

테스트

  • 예외 케이스 고려

My Code

cpp

boj/8979.cpp
// https://www.acmicpc.net/problem/8979
#include <iostream>
using namespace std;
 
#ifdef LOCAL
#    define LOG clog
#else
struct nullstream : ostream {
    nullstream()
        : ostream(nullptr) {}
};
nullstream LOG;
#endif
 
//--------------------------------------------------------------------------------------------------
 
#define MAX (1234567891)
#define MIN (-1234567891)
 
#include <algorithm>
#include <iostream>
#include <vector>
 
typedef struct nation {
    int number;
    int gold;
    int silver;
    int bronze;
 
    bool operator==(const nation& other) const {
        return gold == other.gold && silver == other.silver && bronze == other.bronze;
    }
} Nation;
 
template<typename T, typename Compare>
int partition(vector<T>& arr, int low, int high, Compare cmp) {
    int pivot = high;
    int left  = low - 1;
 
    for (int right = low; right < high; ++right) {
        if (cmp(arr[right], arr[pivot])) {
            left++;
            swap(arr[left], arr[right]);
        }
    }
    left++;
    swap(arr[left], arr[pivot]);
    return left;
}
 
template<typename T, typename Compare>
void q_sort(vector<T>& arr, int low, int high, Compare cmp) {
    if (low < high) {
        int pivot = partition(arr, low, high, cmp);
 
        q_sort(arr, low, pivot - 1, cmp);
        q_sort(arr, pivot + 1, high, cmp);
    }
}
 
int main() {
    //   logic
 
    int n, target;
 
    cin >> n >> target;
 
    vector<Nation> arr;
 
    for (int i = 0; i < n; ++i) {
        int number, gold, silver, bronze;
 
        cin >> number >> gold >> silver >> bronze;
 
        arr.push_back({ number, gold, silver, bronze });
    }
 
    q_sort(arr, 0, arr.size() - 1, [](const Nation& a, const Nation& b) {
        if (a.gold != b.gold) {
            return a.gold > b.gold;
        }
 
        if (a.silver != b.silver) {
            return a.silver > b.silver;
        }
        return a.bronze > b.bronze;
    });
 
    int    rank        = 1;
    Nation rank_before = arr.front();
 
    for (int i = 0; i < n; ++i) {
        if (i > 0) {
            if (!(arr[i] == rank_before)) {
                rank        = i + 1;
                rank_before = arr[i];
            }
        }
 
        if (arr[i].number == target) {
            cout << rank << "\n";
            break;
        }
    }
}